Logarithmic Equations Calculator

SOLUTION
Type the equation, then press = to solve it.
Every root, kept or thrown out
Every log must be in the same base, and every answer is checked before it is kept.
Get to one log on each side, then undo it. A logarithm can only take a positive number, so every answer has to be put back in — the ones that break that rule are called extraneous and must be dropped.
How the equation is solved, step by step

Solve log(x−3) + log x = 1 and the algebra hands you two roots: 5 and −2. Only one of them is an answer.

Put −2 back and the first term asks for log(−5), which does not exist. That root is extraneous, and losing marks to it is what makes these questions harder than they look. This logarithmic equations calculator checks every root against the original equation and shows you which one fails and why.

Logarithmic Equations Calculator — a free tool from Monkza

How to Solve Logarithmic Equations

Every question of this kind reduces to one of two shapes, and getting to one of them is most of the work.

One log equals a number. log(A) = c. Raise the base to both sides and the logarithm disappears: A = 10ᶜ for log, or eᶜ for ln. log(x+1) = 2 becomes x + 1 = 100, so x = 99.

One log equals another log. log(A) = log(B). The same logarithm of two things can only be equal when the two things are equal, so A = B and the logs simply drop away.

If there is more than one log on a side, condense first — adding logs multiplies the insides, subtracting divides them, and a coefficient goes up as a power. Only then undo it.

Why Extraneous Solutions Appear

They are not a quirk. They are built into the method, and knowing why makes them easy to catch.

log(x−3) + log x = 1 only makes sense when x > 3, because both logs need a positive inside. Condense it to log(x²−3x) = 1 and that restriction quietly vanishes — x²−3x is positive for x < 0 as well. The condensed equation allows values the original never did, and −2 is one of them.

So the algebra is not wrong; it is answering a slightly wider question. Putting each root back into the equation you started with is what narrows it again. Solving log equations without that step is only half the method.

How to Use This Logarithmic Equations Calculator

Type the equation and press =. The keypad has log, ln, x and the equals sign, so log(x−3) + log x = 1 is a handful of taps. Both log and ln work, as long as every logarithm in the equation is in the same base.

The answer appears with a note saying how many roots were thrown out. One tap opens every root that came out of the algebra — the ones that survived in green, the ones that failed struck through, each with the exact log that broke and the number it was asked for.

Answers stay exact where they can: log x + log 3 = 1 gives 10/3, not 3.33. Under the working you will find the same five steps you would write on paper, including the check. If you need to join the logs by hand first, the condense logarithms calculator does that part, and the log calculator handles plain values in any base. It is free to use online, with no account.

Logarithmic Equations FAQ

How do you solve a logarithmic equation?
Get to one logarithm on each side, then undo it. If both sides are a log, the insides are equal. If one side is a number c, the inside equals the base raised to c. Solve what is left, then put every answer back into the original equation.
What is an extraneous solution in a logarithmic equation?
A root that comes out of the algebra but breaks the original equation. Joining logs quietly allows values the original never did, so a root can appear that makes some log ask for zero or a negative number. That root has to be thrown out.
Why do you have to check the answers?
Because a logarithm only takes positive numbers. log(x-3) is undefined when x is 3 or less, so any root at or below 3 is not a solution however correct the algebra was. Checking is the only way to know.
Can a logarithmic equation have no solution?
Yes. If every root fails the check, the equation has no solution at all. log(x-5) + log(x-3) = 0 is that kind: the algebra gives two roots and both leave a logarithm undefined.
How do you solve log x = 2?
Raise the base to both sides. log means base 10, so x equals 10 squared, which is 100. With ln it would be e squared instead.

Condense, undo, solve, and then check — and it is the checking that separates a right answer from a plausible one.